A.
Gay- Lussac’s law- Pressure is
directly proportional to the KELVIN temperature if the volume and mass remain
constant.
B.
When a gas is heated at
constant volume, the pressure increases.
C.
When one variable increases,
the other variable increases
EXAMPLE PROBLEM:
The pressure in a car tire is 198 kPa at 27oC. After a long drive, the pressure is 225
kPa. What is the temperature of the air
in the tire? Assume that the volume is
constant.
Given: P1 = 198 kPa , T1 = 27
oC , P2 = 225 kPa
198kPa/27oC
= 225 kPa/ T2
T2 =
225(27)/198
= 30.7oC
The temperature of the air in the tire
after the long drive is 30.7oC.
Evaluate: According to Gay - Lussac's Law, temperature is directly proportional to pressure, and since the pressure increases, the resulting answer is greater than the original temperature.
Evaluate: According to Gay - Lussac's Law, temperature is directly proportional to pressure, and since the pressure increases, the resulting answer is greater than the original temperature.
- Combined gas law
A.
The combined gas law allows you
to do calculations for situations in which only the amount of gas is constant
EXAMPLE
PROBLEM: A 5.00 L air sample has a
pressure of 107 kPa at a temperature of -50.0oC. IF the temperature
is raised to 102oC and the volume expands to 7.00 L, what will the
new pressure be?
Given: V1 = 5.00 L6, P1 = 107kPa , T1 =
-50.0 oC , T2 = 102oC , V2 = 7.00 L
107kPa (5.00L) / -50oC = P2 (7.00L) / 102oC
P2 = (5.00L) (107 kPa) (102oC) / (-50oC)
(7.00L)
= -155.91 kPa
The new pressure is -155.91 kPa after the
temperature was raised to 102 oC and the volume expands to 7.00 L.
Tips for Gas Law
Problems
1) Determine which gas law you need
n
Pressure
and volume = Boyle’s
n
Temperature
and volume = Charles’
n
Temperature
and Pressure = Gay-Lussac’s
n
Temperature,
pressure, and volume = Combined
2) Identify your variables. Be sure you put the proper numbers together
3) Change all variables into the correct units
n
Temperature
must be Kelvin
n
Pressure
units must match
n
Volume
units must match
4) Put numbers into the gas law equation and solve
Ideal gas Law
Goals for this section:
-
Calculate
the value of an unknown variable using the ideal gas law
-
Compare
and contrast real and ideal gases
-
Terms
to know: ideal gas law, ideal gas constant
VI. Ideal Gas Law
A. Ideal gas- A gas that conforms to the gas
laws.
a. Particles exhibit no attractive or repulsive force.
b. Volume of particles is assumed to be
negligible compared to the total volume occupied by the gas. This means you can
ignore the volume of the particles.
B. Real gases do not behave ideally when they
have high pressure or low
temperature.
a. Under these conditions, gases tend to _condense.
C. When
is a gas ideal?
a.
When
it has large volume and low
pressure and/or high temperature.
b.
Under
these circumstances, attractive forces are not important.
D.
ideal gas law: .
P = pressure (must be in
units of kPa)
V = volume (must be in units
of L)
n = moles (may need to
convert grams or molecules to moles first)
R = 8.31 LkPa/(Kmol)
T = temperature (must be in units of K)
Partial Pressures,
Diffusion, Effusion
Goals for this section:
-
Relate
the total pressure of a mixture of gases to the partial pressures of the
component gases
-
Explain
how the molar mass of a gas affects the rates at which the gas diffuses and
effuses
-
Compare
and contrast effusion and diffusion
-
Terms
to know: partial pressure, Dalton’s law of partial pressures, diffusion,
effusion, Graham’s law of effusion/diffusion
VII.
Partial
Pressures, Diffusion, Effusion
a. Partial Pressure:
i.
The
contribution each gas in a mixture makes to the total pressure is called the partial pressure exerted by that
gas
ii.
Dalton’s
law of partial pressures; In a mixture of gases, the total pressure
is the sum of the partial pressures
of the mixture of each individual gases.
1.
Provided
the temperature and volume remain the same
b. Diffusion is the tendency of molecules to move toward areas of low concentration until the
concentration is uniform throughout
c. During effusion, a gas escapes
through a very small hole in
the container.
d. Gases of lower molar mass diffuse and effuse faster than gases of
higher molar mass.
e.
Graham’s law of effusion states that the
rate of effusion of a gas is inversely proportional to the square root of the
gas’s molar mass. This law can also be applied to the diffusion of gases.
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