Slide show 3 - Gas Laws ( the answer is in order)

8. Given: V1= 4 L; P1= 205 kPa; V2= 12 L 

Required: P2

Solve: V2 = 4 L x 205 kPa / 12 L = 68.3 kPa

Evaluation: An increase in volume at constant temperature must correspond

to a proportional decrease in pressure. The calculated result agrees with both

kinetic theory is expressed to the proper number of significant figures

10. Given: T1 = 50 C + 273 = 323 K; T2 = 100 C + 273 = 373 K; V1= 5 L 

Required: V2

Solve: V2 = 5 L x 373 K / 323 K = 5.77 L

Evaluation: The volume increase as the temperature increase. This result agrees with

 both kinetic theory and Charles’s law

12.Given: T1 = 27 C + 273 = 300 K; P1= 198 kPa; P2= 225 kPa 

Required: T2

Solve: T2 =  225 kPa x 300 K / 198 kPa = 340.91 K

Evaluation: From the kinetic theory, the expected outcome if the pressure

increase, the temperature is also increasing if the volume remains constant.

The calculated value does show such an increase.

14.Given:T1 = 50 C + 273 = 323 K; T2 = 102 C + 273 = 375 K; V1= 5 L; P1= 107 kPa; 

V2= 7 L

Required: P2

Solve: P2 = P1 x V1 x T2 / T1 x V2

P2 = 107 kPa x 5 L x 375 K / 323 K x 7 L = 88. 73 kPa

Evaluation: An increase in volume have opposite effects on the pressure of gas. To evaluate the

Decrease in pressure, multiply the original pressure (107 kPa) by the ratio of V1 to V2 (0.7) and

The ratio of T2 to T1 (1.16). The result is 88.73 kPa